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DOS app - command line?

Started by peter86 8 replies 500+ views
Original Post
peter86
peter86
How do I catch the command line in a DOS app?
JuNC
JuNC
int main(int argc,char** argv)


argc is the count of (space separated) arguments and argv is an array of strings actually containing them.
peter86
peter86
I dosen´t work to me. How do I display the string with printf()? Output is always "9" to me.

[edited by - peter86 on December 30, 2002 11:47:30 AM]
peter86
peter86
int main(int argc, char* argv)
{
printf( argc );
}
cgoat
cgoat
That''s working right, argc is the count.

Try this:


  
int main(int argc, char *argv[])
{
   int nArg;
   for(nArg=0; nArg<argc; ++nArg)
   {
      printf("Arg[%d] = %s\n", nArg, argv[nArg]);
   }

   return 0;
}
peter86
peter86
quote:
Original post by cgoat
That''s working right, argc is the count.


Of course I meant argv, just wrote wrong . Your code dosen´t work either, it just crashes.
Evil Bill
Evil Bill
cgoats code is correct.

What do you mean it crashes? What error message / code? Does it display anything, or just crash before printing anything?

Have you tried debbuging it to see more prescisely what causes the crash?

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