Rounding a float

#include <math.h>

float a = 2.6f;

a = floor(a + 0.5f);

or....

float a = 2.6f;

int b = (int)(a + 0.5f);

I''m not sure why that works, but it does.

Thanks a lot!

quote:

---

Original post by jim bob
I''m not sure why that works, but it does.

---

floor() and (int) both give you the number rounded down, so 1.3 goes to 1, and so does 1.8. But if you add 0.5, then:
(1.3 + 0.5) = 1.8
rounded down goes to 1 (which is correct - 1.3 rounded to the nearest whole number is 1)
but:
(1.8 + 0.5) = 2.3
rounded down goes to 2 (which, again, is correct - 1.8 rounded to the nearest whole number is 2)

Hope that helps you understand it (even though it wasn''t a great explanation)

John B