How to write (square[Array()() - Array2()()]) as code?

  
#include <math.h>

int arr1[10][10], arr2[10][10], int result;

// set the values somewhere to whatever


// I don''t know if you want to keep the values and add up a

// result or what, so I''ll just make a new result every time.


for(int i = 0; i < 10; i++)
 for(int j = 0; j < 10; j++)
  result = sqrt(arr1[i][j] - arr2[i][j]);