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Suspicious parameter.

Started by KurtCPP Oct 20, 2003 at 4:33 AM 2 replies 400+ views

Original Post

Oct 20, 2003 at 4:33 AM

Hi''ve seen in a book a statement looking like the following. Couls someone shed light on this, please? Function(double = 0); I cant remember whether it was declaration but I still think it was. What does double = 0 do here?? Thanks to all in advance. Prog, Hex & Rock''n''Roll : I don''t like the Prog but the Prog likes me. Some nice poetry to sweeten your spirit and relax a bit before programming

Blutdurst

Oct 20, 2003 at 4:37 AM

Hi!

The double=0 puts 0 per default to the first paraemter of the function.
So, for the function call, it is optional to specify the parameter. If none is specified, the value is 0, otherwise, it''sthe value given

regards
Blutdurst

KurtCPP

Author

KurtCPP

Oct 21, 2003 at 1:21 AM

OK but what if I still wanna specify a parameter name?? Shall I simply write double fValue = 0?? I suppose it gotta be this since a parameter w/o name would be kinda useless according to me...

Prog, Hex & Rock''n''Roll :
I don''t like the Prog but the Prog likes me.
Some nice poetry to sweeten your spirit and relax a bit before programming

GroZZleR

140

GroZZleR

Oct 21, 2003 at 1:25 AM

As far as I can tell, you''re just getting hung up on the concept that its not specifiying a name in the prototype, where as in the definition, you would have to.

Example:
Function(int, int, int);

Is perfectly fine, and would be defined like:
Function(int x, int y, int z)
{
return x + y + z;
}

So yes, if you want to specifiy a name in the prototype, go right ahead.

Function(double MyDouble = 0);

Is just fine.

I personally prefer the latter, to put names with my prototypes.

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