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math question(or physics)

Started by Tyro 2 replies 1.3k views
Original Post
Tyro
Tyro
when graphing y=mx, the slope is dy/dx. Is there a way to calculate the slope without using x values? this question came up when i was asked to look for the elementary charge of an oil droplet (Millikan''s oil drop experiment). the sheet gives a list of charges taken from a single drop of oil, and we have to find a number that divides each of them evenly. Trying to find out the greatest common factor didnt work, because first number is 6.563 x 10 ^-19 (i dont know how to factor it) Next i expresssed everything to q=Ne so q1=n1e q2=n2e .. ... but instead of n2, i expressed that in terms of n1, and put 1.25n1, making it q2=1.25n1e. i just divided q2 by q1 to get the ratio and applied it to n. But now i cant get the slope to get e, because my x values are all in terms of N, if i dont get that number i cant get the slope. my slope is like 6.563/N1 i''ll post all the values. 6.563 x 10 ^-19 C 8.204 x 10 ^-19 C 11.50 x 10 ^-19 C 13.13 x 10 ^-19 C 16.48 x 10 ^-19 C 18.08 x 10 ^-19 C 19.71 x 10 ^-19 C 22.89 x 10 ^-19 C 26.13 x 10 ^-19 C
d_code
d_code
try looking at the change between each of the charges, it will be MUCH easier to see the common factor.

i.e
6.563 - 8.204 = -1.641
8.204 - 11.5 = -3.296


... basically all the charges should be a mutliple of 1.6x10^-19
Tyro
Tyro
hrm algebraically i can see how the differences have same factor as the original but i dont get how most of the differences turn out to be the elementary factor.

is this a method of finding a common factor or does it work only in this case?

After ive gotten differences i would try to find the exact common factor by trial and error but is there another way?
Tron3k
Tron3k
The differences make it easier because each difference will be about 1, 2, or 3 times the common factor.
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