pointer question

a quick way is:

char * GetPointer(unsigned int myAddress) {
   union {
      char *          thePointer;
      unsigned int    theValue;
   } myConvertor;

   myConvertor.theValue = myAddress;

   return myConvertor.thePointer;
};

This is a very basic technique, and there are probably 100 ways to do the same thing. The assembly code is actually quite small, since all my syntax here is just "c" fluff, where no asm is generated, thus performance should be fast..

What''s wrong with ((void *) 0x00FF00F0)?

CoV

Both versions work great. However if I use the following to display the address: cout<<&pointer<Its not the same as what I entered.
Why?
-CProgrammer

Because "&pointer" is the address of the pointer variable, not the address of the object that the pointer points at. The address of the object that the pointer points at is just "pointer".

CoV

Ay, offcourse, thanks
-CProgrammer