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RECT collision detection.

Started by maxd gaming Feb 4, 2004 at 2:53 PM 2 replies 300+ views

Original Post

Feb 4, 2004 at 2:53 PM

I have the corrod''s of my 2 objects stored in RECTS (they are 2d) and I want to see if they have collided (via a 2d bounding box in rects) please help (source would be nice) doesn''t matter which language cause it is easy to figure out... HELP!

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oliii

270

oliii

Feb 4, 2004 at 3:19 PM


bool collided(RECT* r1, RECT* r2)
{
    if (r1->bottom < r2->top || r2->bottom < r1->top) return false;
    if (r1->right < r2->left || r2->right < r1->left) return false;
    return true;
}

maxd gaming

Author

maxd gaming

Feb 4, 2004 at 6:12 PM

quote:

Original post by oliii


bool collided(RECT* r1, RECT* r2)
{
    if (r1->bottom < r2->top || r2->bottom < r1->top) return false;
    if (r1->right < r2->left || r2->right < r1->left) return false;
    return true;
}

Whoa... perfect thanks you are my god

It''s Maxd Gaming, put in an underscore and I will beat you with a rubber ducky!
{ My Site! - Banner } { My Site! - One time popup }{ My .Net Information }{ A upcoming space RTS codenamed Gruntacktica

. }{ . }

Not following the new trend:
Looky here mommy! No cow pic!

Phoe''s Forums

oliii

270

oliii

Feb 5, 2004 at 3:06 AM

I might as well tell you how you can find the intersection depth, then you can push the player away from the tile.


// r1 = player, r2 = tile, push = direction to push the player

bool collided(RECT* r1, RECT* r2, POINT* push)
{
    float y0 = r1->top - r2->bottom;
    float y1 = r2->top - r1->bottom;
    if (y0 > 0.0f || y1 > 0.0f) return false;

    if (abs(y1) < abs(y0))
         push->y = y1;
    else
         push->y = -y0;

    float x0 = r1->left - r2->right;
    float x1 = r2->left - r1->right;
    if (x0 > 0.0f || x1 > 0.0f) return false;

    if (abs(x1) < abs(x0))
         push->x = x1;
    else
         push->x = -x0;

    if (abs(push->x) < abs(push->y))
         push->y = 0;
    else if (abs(push->y) < abs(push->x))
         push->x = 0;
 
    return true;
}

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