converting to binary

Hmm, smells like homework. What have you tried already? How are you thinking of going about it? What problems have you run into?

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"Sneftel is correct, if rather vulgar." --Flarelocke

int n = 5;
String s = "";

int counter = 0;

while(n > 0)
{
int r = n%2;
s = (char)(''0'' + r) + s;
n = n/2;
}

well i have that but that''s in java. i need to convert it to c++.

What do you mean by "convert"? Numbers are always stored in binary, doesn''t matter if it''s an integer or a float. You usually just can''t access them in their binary form in the source-code. Instead, use hexadecimal representations. If you really really need to access them as binary, write a function that takes care of it.

In the Delphi language, that''d be something like this:

// Function IntToBinary takes a byte (unsigned 8-bit int) and returns a string
function IntToBinary(YourInteger : Byte): String;
begin
	case (YourInteger) of 
		// Hex notation in Delphi is done with a $ sign before the number
		// Result is equivalant to C++''s "return" statement
		$0 : Result := Result + ''0000'';
		$1 : Result := Result + ''0001'';
		$2 : Result := Result + ''0010'';
		$3 : Result := Result + ''0011'';
		$4 : Result := Result + ''0100'';
		$5 : Result := Result + ''0101'';
		$6 : Result := Result + ''0110'';
		$7 : Result := Result + ''0111'';
		$8 : Result := Result + ''1000'';
		$9 : Result := Result + ''1001'';
		$A : Result := Result + ''1010'';
		$B : Result := Result + ''1011'';
		$C : Result := Result + ''1100'';
		$D : Result := Result + ''1101'';
		$E : Result := Result + ''1110'';
		$F : Result := Result + ''1111'';
	end;
end;
 

Let me get this straight. In order to complete your homework assignment, so far you''ve copy-and-pasted code you found on the internet, and now you want people to convert it from Java to C++ for you? Yikes.

---

"Sneftel is correct, if rather vulgar." --Flarelocke

i just want to know what this will be in c++

int n = 5;
String s = "";

int counter = 0;

while(n > 0)
{
int r = n%2;
s = (char)(''0'' + r) + s;
n = n/2;
}

Yes, I know. Read the Forum FAQ on homework questions, and repost once you''ve done some real work.

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"Sneftel is correct, if rather vulgar." --Flarelocke