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getting array/pointer out of function

Started by pixienick Aug 11, 2004 at 8:42 AM 4 replies 700+ views

Original Post

Aug 11, 2004 at 8:42 AM

I got a function which builds a massive buffer of data in an array. I just cant seem to get this array out of the function like either; void function(float *data) { data = new float[lots]; for(i) { data = something } } or float *function() { data = new float[lots]; for(i) { data = something } return data; } the data is never filled outside/after the function, know what i mean? any suggestions much appreciated cheers

Kippesoep

Aug 11, 2004 at 8:44 AM

Either use the return value, or use a pointer reference:

void function (char *&data){  data = new char [1024];}

pixienick

Aug 11, 2004 at 9:05 AM

Nice one Kippesoep, i never seen such a combo before (&*) - works a treat!

snk_kid

Aug 11, 2004 at 9:19 AM

Quote:
Original post by pixienick
Nice one Kippesoep, i never seen such a combo before (&*) - works a treat!

Think about it pointers are just variables aswell so it's still pass by value except your making a copy of address instead of the instances it refers to

because you wont to modify the pointer passed in you need to either use pointer to a pointer or a reference to a pointer, references are better because no copy is made what gets passed in is what will actually be used.

pixienick

Aug 11, 2004 at 9:35 AM

tis all makes perfect sense once you get it working but intricacies like that can hold one up for hours when you dont know!
(or maybe thats just me)

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