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Function pointers

Started by Daos Aug 30, 2004 at 7:13 AM 2 replies 800+ views

Original Post

Aug 30, 2004 at 7:13 AM

Why this initialization doesn't work? where the arguments are pointers to functions... int(*checkf[6])(unsigned __int64& mutare)={checkPawn,checkRock,checkKnight,checkBishop,checkKing,checkQueen}; ERROR<>'initializing' : cannot convert from '' to 'int (__cdecl *)(unsigned __int64 &)'

I guess it's something about calling convention......

Ruben3d

Aug 30, 2004 at 7:29 AM

try this:

int(*(checkf[6]))(unsigned __int64& mutare)={checkPawn,checkRock,checkKnight,checkBishop,checkKing,checkQueen};

or this:

int(*checkf[])(unsigned __int64& mutare)={checkPawn,checkRock,checkKnight,checkBishop,checkKing,checkQueen};

or maybe a mix of the two previous:

int(*(checkf[]))(unsigned __int64& mutare)={checkPawn,checkRock,checkKnight,checkBishop,checkKing,checkQueen};

This last attempt appears to be correct, according to the operator precedence table shown here.

Daos

Author

Daos

Aug 30, 2004 at 7:42 AM

Sorry my mistake the definitions of the function were OK
but the prototypes were not So I freked out that's a calling convention problem.Sorry for wasting your time.Thanks anyway![smile]

doynax

Aug 30, 2004 at 1:36 PM

Quote:
Original post by Daos
Sorry my mistake the definitions of the function were OK
but the prototypes were not So I freked out that's a calling convention problem.Sorry for wasting your time.Thanks anyway![smile]

Here's a tip: Typedef complex types! It'll save you a lot of headaces when dealing with function pointers and stl containers.

typedef int (*check_piece)(unsigned __int64 &mutare);check_piece checkf[] = {  checkPawn, checkRock, checkKnight, checkBishop, checkKing, checkQueen };

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