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Even more #define macros

Started by Rob Loach Mar 17, 2005 at 8:10 PM 2 replies 500+ views

Original Post

Rob Loach

219

Rob Loach

Mar 17, 2005 at 8:10 PM

Is it possible to get const char arrays through a macro? Something like this:

#define CrazyFunction(x) void  ## x ## (int b)

// Then for a function definition you'd go:
CrazyFunction("Hello"){
    // Function code
}

Or is it only possible with numbers?

Evil Steve

382

Evil Steve

Mar 17, 2005 at 8:24 PM

Nope, you can't do that. However, you can pass Hello to the function, and use #x if you need to convert to a const char*

EDIT: Some code:

#define Func(x) printf("%s",#x);Func(Hello)

Ok, that's a really bad example :P

Sneftel

297

Sneftel

Mar 17, 2005 at 8:46 PM

I'm confused.... are you trying to de-stringize a string-constant with the preprocessor? If so, why the heck do you want to do this? The stringizing operator may be sufficient for you.

Drew_Benton

FOUNDER

411

Drew_Benton

Mar 17, 2005 at 9:10 PM

[lol] Rob, here's a start for you:

#include <stdio.h>#include <stdlib.h>#define CF1(x) void _ ## x ## (int b)#define CF2(x,y) CF1(x) { printf("%i",y); abort(); }CF2(HI,2)int main( int argc, char** argv ){	_HI(0); // 0 does not work b/c of the 2 above	return 0;}

You were close to being with, but see what I did to get around the error you had, with the "_" and space?[wink]. I think I know what you are trying to do, and I think I had tried it before and could not get it to work, but then again, I could not of had made this code work either. Something to play with. I will work with this though, I think you may be able to do some intresting stuff with this.

- Drew

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