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[java] New Q: Random #'s in Java

Started by lupine Nov 7, 2000 at 1:56 PM 3 replies 500+ views

Original Post

Nov 7, 2000 at 1:56 PM

I am coming from a different programing language and learning java. I think I am stating to "get it" If someone has time could you please post a simple java application program (start to finish) Which does the folowing: display a random # (1-6) on screen Thank You, and np if you don''t have time.

loserkid

Nov 7, 2000 at 2:12 PM

Hello :

here it is (simple as that):

     
public class SimpleApp {

  //Main method

  public static void main(String[] args) {
     // ranNum is the Random number 

     int ranNum = (int)(1 + Math.random() * 6); 
     System.out.println(ranNum);
  }
}

This is a simple java app that will display a random number (1-6) it will run as a console program (in dos) since you weren''t specific about whether it was a window(ed) app or console app.

JP.

==============================================
I feel like a kid in some kind of store...
==============================================
www.thejpsystem.com

lupine

Nov 7, 2000 at 3:12 PM

Thanks JP.
Seeing this code answers alot
of questions for me and having
it as a reference will also help
I have a follow up question.
You said this will run in DOS.
Being Java, wouldn''t it run
anywhere?

loserkid

Nov 7, 2000 at 4:33 PM

What I meant it is a console application and i used DOS as an example of where the app will run. it could run in the linux console and others, etc. (it''s not going to generate a windowed app)

JP.

==============================================
I feel like a kid in some kind of store...
==============================================
www.thejpsystem.com

deakin

Nov 9, 2000 at 4:35 AM

There is another method you can use like this:

  
// create new random object and seed it with time

Random random = new Random(System.currentTimeMillis());

// Returns a random number in the given range

private int getRandomNum(int range){
	return Math.abs(random.nextInt() % range);
}

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