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pointing pointers

Started by guyaton Apr 6, 2005 at 2:47 PM 4 replies 650+ views

Original Post

Apr 6, 2005 at 2:47 PM

I am trying to use a pointer to point to a pointer. a simplified version of what I am doing looks like this:


int **someI = NULL;
someI = new int*[1];
someI[0] = new int;

after executing the second line, someI is still = 0x00000000. what am i doing wrong? ~guyaton

doho

Apr 6, 2005 at 2:56 PM

Quote:
Original post by guyaton
after executing the second line, someI is still = 0x00000000. what am i doing wrong?

Nothing from what I can see. For me, after the second line is executed someI isn't NULL.

guyaton

Author

guyaton

Apr 6, 2005 at 2:59 PM

I started it in a new program and it works fine....weird. i wonder y in my program it doesn't work.

crusadingknight

Apr 6, 2005 at 4:25 PM

Quote:
Original post by guyaton
I started it in a new program and it works fine....weird. i wonder y in my program it doesn't work.

You're certain you're not setting it to NULL or redeclaring it elsewhere by acccident? :\ Otherwise, that shouldn't be possible, unless it's in an uncalled function.

Qw3r7yU10p!

Apr 6, 2005 at 5:04 PM

Quote:
Original post by guyaton
I am trying to use a pointer to point to a pointer.

So you're almost a ThreeStarProgrammer.

you could use std::vector to make things simpler.

std::vector<int*> someI(1);someI[0] = new int;//or evenstd::vector<int> someI(1);

Omaha

Apr 6, 2005 at 9:27 PM

1.) How are you checking that it is in fact NULL?
2.) Are you sure you aren't actually looking at the dereferenced value, which may or may not cause the program to explode?
3.) If you only need one, why are you using an array?

"Simplified versions" of code snippets frequenty simplify out the issue.... Are you sure there's not something else happening in there?

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