code error

#include <cstdlib>#include <iostream>#include <fstream>#include <string>using namespace std;int main(int argc, char *argv[]){    //argc is the amount of arguments given to this program    //while argv is those arguments    if(argc < 2)               //not enough arguments, exit    {      cout << "Usage: this.exe input_file" << endl;      cout << "Args: " << argc << endl;      return 0;    }        ifstream in;               //declare a input stream    in.open(argv[1], ios::in); //use the second argument as the file to read    in.seekg(0, ios::end);     //seek to the end of the file    int size = in.tellg();     //get the amount of bytes seeked    in.seekg(0, ios::beg);     //return the beginning of the file        if(size <= 0)              //if the file is empty, exit     {                          //also, bad files give a negative value for size      cout << "Bad or empty file.. exiting" << endl;      return 0;    }        string line="";            //declare a string    while(!in.eof())           //while we haven't reached the end of file    {      getline(in, line);       //read in till we reach a '\n'      cout << line << endl;    //output this to the screen    }    in.close();                //close the input stream we opened    system("PAUSE");               return 0;}

#include <iostream>#include <fstream>int main(int argc, char *argv[]) {  using namespace std;    if(argc != 2) // Wrong number of arguments, exit.   {    cout << "Usage: " << argv[0] << " [input_file]" << endl;    return -1;   }    ifstream in(argv[1]); // Open the file.    if(in) // If the file is good for I/O operations, we'll copy it's buffer to cout:   cout << argv[1] << " contains: " << endl << in.rdbuf() << endl;  else   cout << "Couldn't open " << argv[1] << "." << endl;    // No need to close the file, ifstream will do that in it's destructor.    return 0; }