Parsing "command" for a string?

// Basic Script.cpp : Defines the entry point for the console application.//#include "stdafx.h"void ParseCommand(const char *szCmd) {	char szCmdName[15], szParam1[256];	if (strstr(szCmd, "print"))       // Command is 'print'; print specififed string to screen	{		strcpy(szCmdName, "print");   // Copy the command name		int p = (strlen(szCmdName) + 1);   // Index for loop, etc.; make equal to index of first space in 'szCmd'		if (szCmd != '\"')     // No opening quotation mark?		{			cout << "Error. No string specified in \"print\".\n";    // Print error			return;     // Return from function		}		else     // Opening quotation mark		{			char szString[256];    // Parameter (string) to 'print'			if (szCmd[strlen(szCmd)-1] != '\"')      // No closing quotation			{				cout << "Error. Must close string with `\"` character.\n";   // Print error				return; // Return from function			}			p++;    // Increment the counter			do     // Enter a 'do ... while' loop			{				if (szCmd == '|')       // New-line character					szString[p-7] = '\n';  // Convert character at 'p-7'				else     // Not a special character				szString[p-7] = szCmd;  // Copy the character				p++;     // Increment the counter			} while (szCmd != '\"');      // As long as we are not at the end of the string			szString[p-7] = '\0';    // Null-terminate the string			cout << szString;    // Print the string			cout << "\n";        // Print a new line		}	}}int main(int argc, char* argv[]){	ParseCommand("print \"I am a test string. 'print' me! :)\"\0");    // Parse a basic command	return 0;}