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Mouse position

Started by smittix Oct 15, 2005 at 8:17 AM 6 replies 550+ views

Original Post

Oct 15, 2005 at 8:17 AM

I need to find the X and Y position of the mouse in respect to its window, but the current method I am using includes the width and height of the title bar and side of the window into the position: xPos = (LOWORD(lParam)); yPos = (HIWORD(lParam)); How do I find the position of the mouse within the actual window area, not including the title bar or sides of the window? Thanks, Chris

SiCrane

Oct 15, 2005 at 8:30 AM

Which message are you using for that code?

smittix

Oct 15, 2005 at 8:37 AM

It is the lParam from the windows callback function.

SiCrane

Oct 15, 2005 at 8:45 AM

And which message are you processing when you run that code?

smittix

Oct 15, 2005 at 9:11 AM

It is caught like this:

LRESULT CALLBACK WndProc(HWND hwnd, UINT msg, WPARAM wParam, LPARAM lParam)
{
switch( msg )
{
case WM_DESTROY:
::PostQuitMessage(0);
break;
case WM_KEYDOWN:
if( wParam == VK_ESCAPE)
::DestroyWindow(hwnd);
break;
}

xLast = xPos;
yLast = yPos;
xPos = (LOWORD(lParam));
yPos = (HIWORD(lParam));

return ::DefWindowProc(hwnd, msg, wParam, lParam);
}

xeddiex

Oct 15, 2005 at 1:43 PM

WM_MOUSEMOVE :xPos = LOWORD(lParam);yPos = HIWORD(lParam);

Endar

Oct 16, 2005 at 1:56 AM

I've never actually seen someone use the "::" global namespace specifier.

I mean, I'm not critisicing, but, when you don't specify any other namespace, isn't the global namespace kind of implied?

risingdragon3

Oct 16, 2005 at 2:53 AM

No.

The lookup process looks at the namespace that the scope is currently in first. There are other various cases, like Koenig lookup and stuff, but that's really complicated. Still, the main point is that the namespace you are in is looked up first.

#include <iostream>void print() {  std::cout << "NO!!!\n";}namespace a {  void print() {    std::cout << "Hi!\n";  }  void DoStuff() {    print();    ::print();  }}int main() {  a::DoStuff();}

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