We say that person A dominates person B if and only if A is taller than B and A is heavier than B.
Which of the following statements MUST be true?
(i) If A dominates B and B dominates C, then A dominates C.
(ii) If A dominates B, then B must not dominate A.
(iii) If A does not dominate B, then B must dominate A.
A. (ii) only
B. (i) and (iii) only
C. (ii) and (iii) only
D. None of the above
Statement(iii) is of coz incorrect so the option B is incorrect. But why is statement(i) not true?
🔒 Locked
a logic question
Advertisement
Original Post
answer: none of the above.
i and ii must be true.
Proof for i: replacing the "dominate" by meaning of dominate, we get:
(A is heavier than B AND
A is taller than B) AND
(B is heavier than C AND
B is taller than C)
=
A is heavier than B AND
B is heavier than C AND
A is taller than B AND
B is taller than C
From first two it follows that A is heavier than C. From second two it follows that A is taller than C. Thus A dominates C.
iii is not necessarily true because a can be heavier AND shorter than b . In this case neither dominates.
i and ii must be true.
Proof for i: replacing the "dominate" by meaning of dominate, we get:
(A is heavier than B AND
A is taller than B) AND
(B is heavier than C AND
B is taller than C)
=
A is heavier than B AND
B is heavier than C AND
A is taller than B AND
B is taller than C
From first two it follows that A is heavier than C. From second two it follows that A is taller than C. Thus A dominates C.
iii is not necessarily true because a can be heavier AND shorter than b . In this case neither dominates.
The first two replys are true. Therefore ... I got nuttin to add.
Dominate(A,B) = (Height(A) > Height(B) && Weight(A) > Weight(B))
i. If Dominate(A,B) && Dominate(B,C) Then Dominate(A,C)
or: If (Height(A) > Height(B) && Weight(A) > Weight(B)) && (Height(B) > Height(C) && Weight(B) > Weight(C)) Then (Height(A) > Height(C) && Weight(A) > Weight(C))
This is the transitive property of inequality in a slightly more complex form. This is a valid proposition.
ii. If Dominate(A, B) then ~Dominate(B, A)
or: If (Height(A) > Height(B) && Weight(A) > Weight(B)) Then ~((Height(B) > Height(A) && Weight(B) > Weight(A))
or: If (Height(A) > Height(B) && Weight(A) > Weight(B)) Then (Height(B) < Height(A) || Weight(B) < Weight(A))
Since the conditional part of the proposition asserts that Height(A) > Height(B), it is necessary that Height(B) < Height(A). Therefore, the resultant part of the proposition is true by default. This is a valid proposition by virtue of tautology.
iii. If ~Dominate(A, B) then Dominate(B, A)
or: If ~(Height(A) > Height(B) && Weight(A) > Weight(B)) Then (Height(B) > Height(A) && Weight(B) > Weight(A))
or: If (Height(A) <= Height(B) || Weight(A) <= Weight(B)) Then (Height(B) > Height(A) && Weight(B) > Weight(A))
Counterexample: Height(A) = Height(B)
Counterexample: Weight(A) = Weight(B)
This is not a valid proposition.
(i) and (ii) are valid, (iii) is not. Answer is D.
i. If Dominate(A,B) && Dominate(B,C) Then Dominate(A,C)
or: If (Height(A) > Height(B) && Weight(A) > Weight(B)) && (Height(B) > Height(C) && Weight(B) > Weight(C)) Then (Height(A) > Height(C) && Weight(A) > Weight(C))
This is the transitive property of inequality in a slightly more complex form. This is a valid proposition.
ii. If Dominate(A, B) then ~Dominate(B, A)
or: If (Height(A) > Height(B) && Weight(A) > Weight(B)) Then ~((Height(B) > Height(A) && Weight(B) > Weight(A))
or: If (Height(A) > Height(B) && Weight(A) > Weight(B)) Then (Height(B) < Height(A) || Weight(B) < Weight(A))
Since the conditional part of the proposition asserts that Height(A) > Height(B), it is necessary that Height(B) < Height(A). Therefore, the resultant part of the proposition is true by default. This is a valid proposition by virtue of tautology.
iii. If ~Dominate(A, B) then Dominate(B, A)
or: If ~(Height(A) > Height(B) && Weight(A) > Weight(B)) Then (Height(B) > Height(A) && Weight(B) > Weight(A))
or: If (Height(A) <= Height(B) || Weight(A) <= Weight(B)) Then (Height(B) > Height(A) && Weight(B) > Weight(A))
Counterexample: Height(A) = Height(B)
Counterexample: Weight(A) = Weight(B)
This is not a valid proposition.
(i) and (ii) are valid, (iii) is not. Answer is D.
Too bad MooMansen is banned. Otherwise he could tell us all how wrong we are.
Topic Locked
This topic has been locked by a moderator. New replies are not allowed.
Sign in to reply to this topic.
Advertisement