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[.net] Regular Expression Problem

Started by coolblue Dec 5, 2005 at 11:52 AM 3 replies 450+ views

Original Post

Dec 5, 2005 at 11:52 AM

I am using the following code to validate a uk 11 digit phone number. Regex expression=new Regex("/^([0-9]{11})$/"); Match m=expression.Match("12345678901"); if(m.Success==true) { return true; } else { return false; } this is not working though. Is this correct?

_DarkWIng_

Dec 5, 2005 at 12:16 PM

Try something like:

return Regex.IsMatch( "0123456789012", @"^([0-9]{11})$" );or evenreturn Regex.IsMatch( "0123456789012", @"^(\d{11})$" );

coolblue

Author

coolblue

Dec 5, 2005 at 5:40 PM

Thank you. Why do all the examples on the net show \^ and $/ instead of just ^ or $?

109

Dec 5, 2005 at 5:42 PM

/^...$/ is the Perl way of doing regular expressions. They begin and end with /.

Sneftel

297

Sneftel

Dec 5, 2005 at 5:43 PM

Becase regular expressions were first commonly used (IIRC) in sed, which bracketed them in slashes. Later, Perl (which is a common consumer of regexes) did the same by default.

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