Redeclaring an array

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Original post by Iccarus any header files needed for that? isn't it?

std::vector<int> maparray(length);

std::vector<int> maparray;

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Original post by Iccarus std::vector maparray[length]; is that the correct initialisation (sorry I haven't used vectors before)

vector<int> vec;// note that even though we dont specify the length, the vector will ensure there is enoughfor( int i = 0 ; i < 10 ; ++i )   vec.push_back(i);// adds the number to the back of the vectorfor( int i = 0 ; i < vec.size() ; ++i )   std::cout << vec << '\n';

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Original post by rip-off use this if you want to start with them zeroised std::vector maparray(length,0);

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Original post by SiCrane Quote: Original post by rip-off use this if you want to start with them zeroised std::vector maparray(length,0); The 0 is unncessary. When you specify an initial size with the constructor, it automatically zeros the vector elements when the vector is of int type.

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Original post by rip-off sweet. specialised templates i assume. didnt know that.

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Original post by SiCrane No. The sized constructor for std::vector<> looks like: explict vector(size_type n, const T & value = T(), const Allocator & allocator = Allocator()); The vector is constructed with n elements copy constructed from value. When no value is specified, the default argument used is T(), which in the case of T being int, turns into 0.

int main() {  int i; // not initialized to anything  int j = 0; // initialized to 0  int k(0); // initialized to 0  int l = int(); // initialized to 0  int m(); // not an int, but instead a function declaration :)  m();}int m() {  return 42;}

float f;int i(f);      // Warning: converting from float to intint j(int(f)); // Let's try an explicit cast... gah, a function declaration! (*int k((int)f); // Okint m(int());  // No bonus, again a function declaration :P

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Original post by Sharlin And it gets better: float f;int i(f); // Warning: converting from float to intint j(int(f)); // Let's try an explicit cast... gah, a function declaration! (*int k((int)f); // Okint m(int()); // No bonus, again a function declaration :P *) I wonder why the grammar allows parentheses around the variable name in a variable declaration in the first place...

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Original post by Zahlman That's not... oh, you mean parentheses around the parameter name in a function declaration.

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Any word on whether 0x will clean this mess up?