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compiling generated code

Started by dathui Apr 9, 2006 at 6:05 PM 1 replies 700+ views

Original Post

Apr 9, 2006 at 6:05 PM

What would be the easiest way to generate executable files from a file? say i got my generator.exe and depending on input want to compile either


#include <iostream>
int main() { std::cout <<"Foo" <<endl; }


#include <iostream>
int main() { std::cout <<"Bar" <<endl; }

One way would be to just generate a source-file and then using cl.exe and link.exe from the visual toolkit, but i wonder if there's another way.

smart_idiot

184

smart_idiot

Apr 9, 2006 at 6:09 PM

I don't know the proper way to invoke cl from the comand line, but with GCC. . .

#include <iostream>int main() { std::cout << BAZ << std::endl; }

g++ myfile.cpp -DBAZ=\"Foo\" -o myprogram

Alternately,

#include <iostream>int main(){  #if version == 1    std::cout << "Foo" << std::endl;  #elif version == 2    std::cout << "Bar" << std::endl;  #else    #error version isn't 1 or 2  #endif}

g++ myfile.cpp -Dversion=1 -o myprogram

You want a better variable name than version though, that's likely to be used in a program, wouldn't want every instance of it to get replaced with a 1, would you?

There should be something similar with your compiler. Read thy documentation.

dathui

Author

dathui

Apr 10, 2006 at 4:04 AM

yea that's what i meant with using cl.exe and link.exe, it's the windows version of what you said. What i'm wondering is if there's another way.

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