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Try const int maxcnt; (or unsigned int or watever u want to use)

It's not legal C++.

1) Default-int is not supported by C++ (you must say "const TYPE maxcnt;" where type is probably int).

2) maxcnt is not a compile-time constant and cannot be used as the dimension of a static array. If you think about this, it should be obvious: with the right constructor, such as one that takes an int parameter and initialized maxcnt with that int, maxcnt can have different values per instantiation of A, which would allow for A's of differing sizes, which would break more language features than you'd care to think about. You'll need to use dynamic allocation or std::vector instead. The latter is preferable to the former; if you must use the former, consider an appropriate "smart" pointer object.

3) You actually have to give the constructor a body, even when you specify an initializer list (such as: "A():maxcnt(100) { }").

it'll work if you say

class A
{
static const int maxcnt = 100;
int m_log[maxcnt];
};

buut yeah you can't initialize 'maxcnt' in the constructor and use it as an array size or something.

Heap anyone?

Quote:

Original post by derek7 class A { const maxcnt; int m_log[maxcnt]; A():maxcnt(100) };

Let's assume that's valid C++ for a moment. What is the size of the object before it's constructed? What's the size of the object after it's constructed? sizeof() is evaluated at compile-time, but the size isn't known till runtime.
Basically, it won't work.

What you can do is:
But I'd second using the heap (Or a std::vector) here.