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[c++] overloading operator ()

Started by sipickles Jul 4, 2008 at 8:07 AM 1 replies 850+ views

Original Post

Jul 4, 2008 at 8:07 AM

Hi, Can anyone tell me if it is possible to overload the call method ()? Heres what I tried: class MyDXDevice { public: IDirect3DDevice9* operator()(void) { return m_device; } private: IDirect3DDevice9* m_device; }; but using MyDXDevice() causes: error C2064: term does not evaluate to a function taking 0 arguments Thanks all! Simon

ToohrVyk

Jul 4, 2008 at 8:14 AM

You need to create an instance.

MyDXDevice device;device();

Hnefi

Jul 4, 2008 at 8:18 AM

Calling MyDXDevice() calls the constructor, not operator(). See example:

#include <iostream>using namespace std;class test{public:  int operator()() {return 5;};};int main(){  test t;  cout << t() << endl; //works fine. Outputs 5.  cout << test() << endl; //ERROR! Attempting to call the constructor, which does not return a type for which operator<< is defined.}

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