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Normal maps - Artists or Code?

Started by Daivuk 0 replies 1.1k views
Original Post
Daivuk
Daivuk
Hi people, When a normal map appear wrong on a model, who to blame? The artists or the code? Can anyone give me tricks to handle that? If you think it's art related, how should they be careful in 3ds max while modeling, and in which direction to setup their normal maps. If it is the code, can somebody tell me what I am doing wrong? Here is how I compute a tangent / bitangent : ( Assuming I am calculing verts[0] for the triangle verts[0..2] )

Edge1.Set(
    verts[1].x - verts[0].x,
    verts[1].y - verts[0].y,
    verts[1].z - verts[0].z);
Edge2.Set(
    verts[2].x - verts[0].x,
    verts[2].y - verts[0].y,
    verts[2].z - verts[0].z);
Edge1uv.Set(
    verts[1].u - verts[0].u,
    verts[1].v - verts[0].v);
Edge2uv.Set(
    verts[2].u - verts[0].u,
    verts[2].v - verts[0].v);

HGfloat cp = Edge1uv.Cross(Edge2uv);

if (cp != 0.0f) 
{
    HGfloat mul = 1.0f / cp;
    tangent   = (Edge1 * -Edge2uv.y + Edge2 * Edge1uv.y) * mul;
    bitangent = (Edge1 * -Edge2uv.x + Edge2 * Edge1uv.x) * mul;

    normal.Set(verts[0].nx, verts[0].ny, verts[0].nz);

    bool inverted = false;
							
    if (normal.Dot(tangent.Cross(bitangent)) < 0) inverted = true;

    if (inverted)
    {
        tangent = normal.Cross(bitangent).Normalize();
        bitangent = tangent.Cross(normal).Normalize();
    }
    else
    {
        tangent = bitangent.Cross(normal).Normalize();
        bitangent = normal.Cross(tangent).Normalize();
    }
}

verts[0].tx = tangent.x;
verts[0].ty = tangent.y;
verts[0].tz = tangent.z;
verts[0].bx = bitangent.x;
verts[0].by = bitangent.y;
verts[0].bz = bitangent.z;



We will eventually rework the Max exporter to get the values 3ds max gives us, but for now I need the artists to visualize at least a correct model. Thanks a lot guys.
Kylotan
Kylotan
Quote:
Original post by Daivuk
When a normal map appear wrong on a model, who to blame? The artists or the code?


If one is wrong, it's art. If all are wrong, it's code. :)

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