array of an array | GameDev.net

Original Post

Jul 21, 2008 at 4:29 AM

So I needed an array of pointers, as this is the only way I could think of allocating memory. Then, I needed to allocate array on the new store using one of those pointers, and finally, get the address of that array. int * array[20] array[0] = new int [500]; //appears legal int **address = &array[0]; **(address + x ) = 1; so what I get is a pointer to a pointer? Is this correct for assignation?

Evil Steve

382

Evil Steve

Jul 21, 2008 at 4:56 AM

Quote:
Original post by VprMatrix89
So I needed an array of pointers, as this is the only way I could think of allocating memory. Then, I needed to allocate array on the new store using one of those pointers, and finally, get the address of that array.

int * array[20]
array[0] = new int [500]; //appears legal
int **address = &array[0];
**(address + x ) = 1;

so what I get is a pointer to a pointer?
Is this correct for assignation?

Yup, that's correct. That last line is the same as:
address[x][0] = 1;
Note that your code only allocates the 2nd dimension of the first element of the array. If you wanted to allocate an 2D array that's 20x500 elements, you'd want to use a for loop:

int* array[20];for(int i=0; i<20; ++i)   array = new int [500];

Zahlman

257

Zahlman

Jul 21, 2008 at 6:25 AM

Just use boost::multi_array and be done with it.

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