Help with C++ method and function names

Original Post

Dec 4, 2008 at 2:11 PM

I have a C++ class ServerSocket which has a method called accept. The accept method calls the accept function but this gives me an error. It tries to execute a version of accept that is part of class definition instead. Is there a way to run the function accept versus the classes method?


int ServerSocket::accept()
{
	int newfd;
	socklen_t size = sizeof(clientAddr);

        //call to the accept function
	if( (newfd = accept(sockfd, (struct sockaddr *)&clientAddr, &size)) == -1)
	{
		return -1;
	}

        return newfd;

}

Mantear

Dec 4, 2008 at 2:14 PM

Try calling "::accept()"

jpetrie

Dec 4, 2008 at 2:14 PM

Use the scope resolution operator to indicate that you'd like the accept method from the global scope: ::accept()

Additionally, consider that the need for an accept() member functions suggests that your socket class is perhaps too low level, and you should improve its overall design and eliminate the function.

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