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Inheriting partial methods?

Started by kaisellgren Apr 23, 2009 at 1:50 AM 4 replies 950+ views

Original Post

Apr 23, 2009 at 1:50 AM

Hi, I have a small problem. I have a base class A and I have a class B which both have the same methods. The thing is, I want the method in A to be run, but I want the same method for B to be run after A to "complete" it. class A { public void do() {...} } class A : B { public void do() {... /* even more */ ...} }

phresnel

124

phresnel

Apr 23, 2009 at 2:12 AM

Your code is neither valid C# nor valid C++, e.g. you derive A from A, and "do" is a reserved keyword. But let me show you both solutions (btw, posting on gamedev ;)

If this is C#:

class A {    public void do_() {        ...    }}class B : A {        new public void do_ () {             ...            base.do_ ()        }}

If this is C++:

class A {public:    void do_() {        ...    }};class B : public A {public:    void do_() {        ...        A::do_();    }};

Rewdew

Apr 23, 2009 at 3:41 AM

And as an additional tip using phresnel's terms (hoho):

B instance;instance.A::do_(); // call A's methodinstance.B::do_(); // call B's method

kaisellgren

Author

kaisellgren

Apr 23, 2009 at 5:40 AM

Thanks!

I wonder why I do not see code tag controls in this writing form?

Zahlman

257

Zahlman

Apr 23, 2009 at 4:29 PM

There is a FAQ linked at the top of every forum page. (It has an icon of an inner tube and magic wand.) You may want to read it :)

rip-off

Mod

445

rip-off

Apr 23, 2009 at 5:16 PM

You could also do something like this:

class A{public:    void whatever()    {        whateverImpl();        finish();    }private:    virtual void whateverImpl() = 0;    void finish();};

Now all derived classes will always have the "finish" code executed when "whatever" is called.

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