easy void * ?

The easiest way is just to make the void* point at the float...

float f,g; // make v point at f... void* v = &f // get the value back out of v g = *(float*)v;

If you really have to store the value of the float in the void*, it is very difficult (impossible?) to do with straight casting, easier to use memcpy()..

memcpy(&v,&f,sizeof(float)); // copy the data to the void* ptr memcpy(&g,&v,sizeof(float)); // copy the data back to a float.

Why would you want to convert a float to a void*? If you want to pass it to some function that accepts a void*, taking the address of the float variable should be enough. Messing with void* is to be avoided (pun intended

Another tip: instead of strtofloat(char string[64]), declare it as strtofloat(const char* str). Specifying the string parameter as a char array of length 64 is not much use, since it will be converted to char* anyway (in standard C). A pointer to a character is sufficient. The const tells that the function doesn''t modify the string.

HTH,
Erik