[Pointer to a vector of pointers] push_back ()

Well, if this is your actual code then it would be because you never initialize vectorOfObjects. Otherwise, what does your debugger say?

SiCrane said it:

std::vector<Object *> vector;std::vector<Object *> *vector_pointer = &vectorvector_pointer->push_back(new Object);

Ah, I see. Thanks, guys.

Your compiler should really give you a warning for this kind of thing. For instance, this is a C4700 for MSVC, which is a level 1 warning. If you warnings enabled at all, MSVC will complain that you're using an uninitialized variable. Compilers emit warnings for a reason. Pay attention to them. If your compiler didn't give you a warning for this, then it's time to get a new compiler.

Quote:

Original post by nGamer Ah, I see. Thanks, guys.

If you're going to use it beyond the current scope, do this:

std::vector<Object *> *vector_pointer = new std::vector<Object *>vector_pointer->push_back(new Object);delete vector_pointer;

The local variable (first line in my first reply) will be destroyed at the end of the scope (that is, when a closing bracket is met '}'). If you want to use the pointer also beyond the scope, you must use dynamic allocation as above. Don't forget to free/delete the memory at the end of the program / when you don't need it anymore!