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What does this code do?

Started by MrLloyd1981 Sep 8, 2011 at 9:41 PM 1 replies 1.8k views

Original Post

MrLloyd1981

Sep 8, 2011 at 9:41 PM

I picked this up from an old programming test found on the web. I understand what it does, as in I can explain in words what happens, but why and where would you use something like this?


 
 What does this code block do?
 
 {
 u_int *source, *end;
 u_int addr_printf, addr_scePrintf;
 int counter = 0;
 
 addr_printf = ((u_int) printf & 0xFFFFFF) / 4;
 addr_scePrintf = ((u_int) scePrintf & 0xFFFFFF) / 4;
 
 source = (u_int *) sceGsSyncPath;
 end = source + 195;
 
 while (source < end)
 {
 if ((*source & 0xFF000000) == 0x0C000000)
 {
 // Function call...
 if ((*source & 0xFFFFFF) == addr_printf)
 { 
 *source = 0x0C000000 | addr_scePrintf;
 counter++;
 }
 }
 
 source++;
 }
 }

jlouts

Sep 8, 2011 at 9:55 PM

looks like a rather hackish way to change code to use a different scePrintf rather than printf. Don't see why you would use it unless you were going to modify some compiled library or something that you don't have the source code to.

ApochPiQ

1,378

ApochPiQ

Sep 8, 2011 at 9:58 PM

Well, let's hear your explanation of what's going on. From that it should be easy to determine what you're missing :-)

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