Float to bits

All data in a computer is stored as bits. So a float in C is already a bit array. Can you specify the question more precisely?

like this click
But a better way and I dont use bitset

Their way:
x /= 2 shifts x right by 1 ( n / 2 = n >> 1)
x % 2 gets the rightmost bit

examples:
3 = 0b11
3 % 2 = 1 (rightmost bit)
3 / 2 = 1
1 % 2 = 1 (rightmost bit)

A much easier way. (bitset constructor)
[font=verdana, arial, helvetica, sans-serif]bitset ( unsigned long val );[/font]
Having said that, what are you trying to do? Why do you need to access individual bits of a float?

Having said that, what are you trying to do? Why do you need to access individual bits of a float?

Agreed, this is all very strange.

Ultimately, the answer is probably "memcpy in to an an array of unsigned char", but I'm not convinced the OP knows what the question is yet

There is nothing strange there, I am using this for spatial partitioning where nodes are represented as binary fractions

Use fixed-point math for that. Then you have floating point fraction as a nice integer.


// 8 bits.
char fraction = static_cast<char>(static_cast<size_t>(float_value * 256.0f) & 0x0ff);