Original Post
How do i (in C++) convert from a char to integer?
example:
input : ''5'' <-- char
output: 5 <-- int
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Input problems...
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cin handles the conversion automatically:
The funny thing is that you can read a character into an integer variable and vice-versa, because all they are is memory locations of different sizes.
#include <iostream>
using namespace std;
int main( int argc, char *argv[] )
{
char c;
int i;
cout << "Input an integer: ";
cin >> i;
cout << i << endl << "input a character: ";
cin >> c;
cout << c << endl;
}
The funny thing is that you can read a character into an integer variable and vice-versa, because all they are is memory locations of different sizes.
To convert from a single char (''containing'' an integer value) to an integer value you can do
(i.e. Just subtract ''0'' from it)
To convert a string (''containing'' an integer) to an integer value you can use atoi() or sscanf()
ex.
|
(i.e. Just subtract ''0'' from it)
To convert a string (''containing'' an integer) to an integer value you can use atoi() or sscanf()
ex.
|
char ch = ''8'';
int val = ch - ''0'';
// now val will contain the integer value
Cool! That worked great. Is there a way to change the integer back into a char?:
example:
input = 8 <-- int
output = ''8'' <--char
int val = ch - ''0'';
// now val will contain the integer value
Cool! That worked great. Is there a way to change the integer back into a char?:
example:
input = 8 <-- int
output = ''8'' <--char
Hmmm. This works good for 1 digit numbers, but what about 2 digit numbers?
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