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why dont this work?!

Started by EvilCrap Dec 28, 2001 at 10:33 PM 8 replies 600+ views
Original Post
EvilCrap
EvilCrap
im trying to do this thing with virtual functions and stuff. where CDog and CCat have base class CAnimal, and private virutal Act() in common: CCat Cat; CDog Dog; CAnimal **Animal = NULL; Animal = new CAnimal*[2]; Animal[0] = &Dog Animal[1] = &Cat Animal[0].Act();//err Animal[1].Act();//err when i call .Act(), i get this compiler error: //error C2228: left of ''.Act'' must have class/struct/union type How can i call these, or am i doing this entire thing wrongly?
Pactuul
Pactuul
"private virutal Act()"

Maybe cause it''s private.....
and when you derive classes they don''t appear....


jeez


Pac
-Pac "The thing I like about friends in my classes is that they can't access my private members directly." "When listening to some one tell about their problem (whether it's code or not), don't listen to what went right or wrong, but what they assumed....."
EvilCrap
EvilCrap
jeez?~!?!?!

you SAY jeez?!!?!?!?

well, mr (knowetall), i happened to have figured it out...

and it should be ->Act();

DUHHHH!!! MVC++ is so dumb, i swear, you think it could spot that.

i swear i cant beleive i wasted so much brain power on dat mistype.
EvilCrap
EvilCrap
hmm sorry maybe my original post wasnt clear
...
where CDog, and CCat, have Base Class CAnimal and private virtual Act() in common.
...
??
DrPizza
DrPizza
I could answer the question.

But it wouldn''t be helpful to do so.

Your compiler ships with documentation, including semi-detailed explanations of the error messages it produces.

Learn how to use them. It will serve you well.

char a[99999],*p=a;int main(int c,char**V){char*v=c>0?1[V]:(char*)V;if(c>=0)for(;*v&&93!=*v;){62==*v&&++p||60==*v&&--p||43==*v&&++*p||45==*v&&--*p||44==*v&&(*p=getchar())||46==*v&&putchar(*p)||91==*v&&(*p&&main(0,(char**)(--v+2))||(v=(char*)main(-1,(char**)++v)-1));++v;}else for(c=1;c;c+=(91==*v)-(93==*v),++v);return(int)v;} /*** drpizza@battleaxe.net ***/
TheBlackJester
TheBlackJester
HeHe,

Gotta love it when people think that a $1,600 program is stupid!

/*
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masonium
masonium
Animal[0] and Animal[1] are pointers, so you have to use the -> operator to access the methods.

CCat Cat;
CDog Dog;
CAnimal **Animal = NULL;
Animal = new CAnimal*[2];
Animal[0] = &Dog
Animal[1] = &Cat

Animal[0]->Act(); // should work now
Animal[1]->Act(); // should work now



No, HTML is not an OO language.
Brannon
Brannon
VC in fact did spot that. What do you think that error message means?



-Brannon
-Brannon
EvilCrap
EvilCrap
yes, i know,

but, it should say at what level ur pointers are messed up at!
!!

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