Function Pointers | GameDev.net

Original Post

Jan 10, 2002 at 12:05 AM

I was wondering if it was possible to get the pointer to a function. I want to have a pointer void *pMyPointer = NULL; and a function void MyFunc( void ) { cout << "Hello" << endl; } and then assign the function to the pointer... pMyPointer = &MyFunc so I can go pMyPointer(); Unfortunatly this does not work. Is there any way that something like this can be done? Thanks.

scaught

Jan 10, 2002 at 12:08 AM

Yup. You want:

  
void (*pMyPointer)(void) = NULL;

pMyPointer = MyFunc;

pMyPointer() will work fine.

-scott

EvilCrap

Jan 10, 2002 at 9:37 AM

rtype (*NAME) (args);

how to cast:

  
        int MyFunction(int,int);
	int (*pMyFunction )(int,int) = MyFunction;
	long pf = (long) MyFunction;
	int x = ((int(*)(int,int))pf)(0,0);
	pMyFunction(0,0);

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