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i need some help

Started by pyro1245 May 31, 2002 at 3:27 PM 5 replies 350+ views

Original Post

pyro1245

May 31, 2002 at 3:27 PM

does anyone know how to find the slope of a line given the angle, starting point, and length? #include <leet>

Erunama

May 31, 2002 at 4:03 PM

This is off the top of my head:


Point A = (Ax, Ay) <-- this is the starting point (which you say is given)

Point B = (Bx, By)
        = (Ax + length*cos(angle),Ay + length*sin(angle))

 Slope  = (By - Ay) / (Bx - Ax)

Hope that is correct.

EDIT: Added code tags to preserve formatting

[edited by - Erunama on May 31, 2002 5:07:20 PM]

pyro1245

Author

pyro1245

May 31, 2002 at 4:29 PM

thanks a lot.

ive been trying to figure out a way to do that for a long time

#include <leet>

pyro1245

Author

pyro1245

May 31, 2002 at 4:50 PM

ok, after further testing of it, there is a problem.

the only angle ot really works on is 0

can you please see if there is a way to fix this

thanks

IndirectX

May 31, 2002 at 5:55 PM

If you have the angle, then the slope is the arctangent of the angle.

Zaphos

May 31, 2002 at 6:31 PM

Yes, double slope = atan(angle);!

Erunama

Jun 1, 2002 at 1:03 PM

pyro: What form are you storing your angles in, degrees or radians? If you are using degrees, then of course you will be having problems because trig functions use radian measure.

To convert, just multiply the degree measurement by 180/PI

Here''s a little real code/pseudo-code:

  
#define PI 3.14159
...
angle = angle*180/PI
sin(angle)

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