delete[] vs delete

Use delete [] n in instances where you have an array of pointers to objects:




And use delete n for single objects:






MatrixCubed
http://MatrixCubed.cjb.net

The main differance is that delete[] will call the destructor for each element of the array while I''m not real sure what delete does. When I tested it it called the destructor, but when I tried accessing a data member I got an access violation.

If you try to access a data member after calling delete, you''ll get a violation because you are now trying to access memory that is no longer allocated to your program. (There is more that happens when you call delete than just executing the destructor)

if you use new className, then use delete
if you use new className[number], then use delete []

That was accessing a member in the destructor, not after calling delete

Thanks matrixcubed. So til today I was only deleting the first instance. However I doubt, and if someone answers this...:

int *ptr_to_int;
int array_of_int[];

ptr_to_int = new int;
array_of_int = new int[40];

Now: is this correct?

delete (ptr_to_int);
delete [] array_of_int;

By the way, matrixcubed, did you receive my email answering about the limit of 1 meg? I''m not sure if I sent it ok since my ISP does whatever it wants when it wants.

Real programers are not afraid from maths! (but I am)
JJpRiVaTe (Private Zone)

Well, other than that you can''t define an open array with out initilization and can''t assign to array_of_int? array_of_int needs to be a pointer as well. One points to one integer and the other points to an array of integers. Then yes it would be right although the parens are not needed.

If you change your code to this:

int *ptr_to_int;
int *array_of_int;

ptr_to_int = new int;
array_of_int = new int[40];

delete (ptr_to_int);
delete [] array_of_int;
 

Then, yes, that is correct.

BTW - why do you insist on putting ptr_to_int inside parantheses? It is not needed and seems like extra shift key typing to me.


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