Quote:Original post by pauls_1979Unfortunately this doesn't work and I think it's because (as MrRowl pointed out) I can't just remove two components, then normalise the quaterni…

18 years, 11 months ago

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18 years, 11 months ago

Perhaps the easiest way is as follows.if p = (1, 0, 0) and q = (0, 1, 0)There are two candidates for the perpendicular to these two vectors, p ^ q, and we chose p ^ q = (0, 0, 1… Forum Reply

Perhaps the easiest way is as follows.if p = (1, 0, 0) and q = (0, 1, 0)There are two candidates for the perpendicular to these two vectors, p ^ q, and we chose p ^ q = (0, 0, 1…

18 years, 11 months ago

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18 years, 9 months ago

Quote:Original post by pauls_1979Unfortunately this doesn't work and I think it's because (as MrRowl pointed out) I can't just remove …

18 years, 11 months ago

Perhaps the easiest way is as follows.if p = (1, 0, 0) and q = (0, 1, 0)There are two …

18 years, 11 months ago

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