Latest crossproduct Activity
Here's the resulting equation for $n = 3$, which is a little bit different than the traditional $3$-D cross product:
result[0] += v(0, 1) v(1, 2)
result[0] -= v(0, 2) v(1, 1)
result[1] += v(0, 0) v(1, 2)
result[1] -= v(0, 2) v(1, 0)
result[2] += v(0, 0) v(1, 1)
result[2] -= v(0, 1) v(1, 0)
For $n = 7…
I figured it all out. Thanks for your ideas!
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