// the integer i want to make a string of.
int a_int = 5;
// the charstring.
char *a_char;
// this is how im trying to do it. i have included stdio.h
sprintf(a_char, "%s", a_int);
// this however makes my program terminate, but if i understand the docs right, this is the way to do it! =(
sprintf
September 10, 2002 10:01 AM
Hello!
I am trying to "convert" a integer to a string so i can print it with TextOut();
However, when i compile, i dont get any errors, but the program terminates imediatly. It runs fine however if i comment the sprintf stuff.
This is how im doing it.
Thanks in advance!
122
September 10, 2002 10:10 AM
hi olle
you must allocate memory for your string
then use
see sprintf (msdn)
dont forget to "free(a_char);"
[edited by - diego_rodriguez on September 10, 2002 11:12:34 AM]
you must allocate memory for your string
a_char = (char *) malloc (16); // reserves 16 bytes which is sufficient then use
sprintf(a_char,"%d",a_int); see sprintf (msdn)
dont forget to "free(a_char);"
[edited by - diego_rodriguez on September 10, 2002 11:12:34 AM]
118
September 10, 2002 10:12 AM
It seems you don''t allocate any memory for your
temporary string a_char. A pointer without
allocation is useless.
If you don''t need a_char in the rest of your
program, you''d better define a array of char
like this :
temporary string a_char. A pointer without
allocation is useless.
If you don''t need a_char in the rest of your
program, you''d better define a array of char
like this :
int i = 123;
char temp_str[80]; // change 80 with the number of characters you need
sprintf( temps_str, "the INT i want to disPLAY: %i", i);
804
September 10, 2002 10:24 AM
conclusion: DONT USE A CHAR*, use a CHAR buffer instead!
This topic is closed to new replies.
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