Euler angles to 3d vector

*breathes in* ok first i would like to state that using Euler angles is not a good way to do camera at all, it has alot of interfierences and tends to break alot...this is one of the problems with them.

to convert euler into a directional vector ((at)-z matrix vector) by getting the matrix out of it

RGT  UP  AT  POS
[x   x   X   x]
[y   y   Y   y]
[z   z   Z   z]
[0   0   0   1]
         ^
         that''s the one you need

psi angle   = Y
phi angle   = p
theta angle = t

here''s the equatiion for the AT vector, you haveto run this to convert it from eulers to the AT vector:

AT = { x = sin(y) * sin(t), y = cos(y)*sin(t), z=cos(t)}

jsut in case you need them, here are the eyesores(i mean the other vectors):

Right = 
{
 x = (cos(y)*cos(p) - cos(t)*sin(p)*sin(y)), 
 y = (-sin(y)*cos(p) - cos(t)*sin(p)*sin(y)),
 z = (sin(t)*sin(p))
}

UP = 
{
 x = (cos(y)*sin(p) + cos(t)*cos(p)*sin(y)), 
 y = (-sin(y)*sin(p) - cos(t)*cos(p)*cos(y)),
 z = (-sin(t)*cos(p))
}
 

...after all consideration you could jsut use matricies, the APIs use them anyways and make code faster , but if you like the eulers, and really wanna use them the math is all there.

~Alexei Andreyevitch Kozlenok

Thanks for the help.

Coin