Pointer to multidimensional array

quote:

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Original post by Anonymous Poster
MARKET ** mDemand = new MARKET[300][300];

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quote:

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Original post by jungle
May I suggest
MARKET (*mDemand)[300]=new MARKET[300][300];

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int max_x = 300;
int max_y = 300;
int* int_array = new int[x * y];

// retrieve element n

int get_element(int x, int y)
{

     return int_array[y * max_x + x];

}

quote:

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Original post by Anonymous Poster
How do you pass a multidimensional array to a function? And how would I access the array inside of the function?

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void PrintFirst(char ** MultDimArray)
{
  cout << "The first string in the string list is: " << MultDimArray[0] << endl;
}

void main()
{
  //it's a lot more intuitive to do this using malloc

  char** MDA = (char**)malloc(num_strings * string_len * sizeof(char*));  

  PrintFirst(MDA);
}

int ****array=new int***[10];

for (int x=0;x<10;x++) {
    array[x]=new int**[10];
    for (int y=0;y<10;y++) {
        array[x][y]=new int*[10];
        for (int z=0;z<10;z++) array[x][y][z]=new int[10];
    }
}

for (int x=0;x<10;x++) {
    for (int y=0;y<10;y++) {
        for (int z=0;z<10;z++) delete[] array[x][y][z];
    }
    for (int y=0;y<10;y++) delete[] array[x][y];
}
for (int x=0;x<10;x++) {
    delete[] array[x];
}
delete[] array;

void foo_func(int (*p)[30][40][50]) {
	// zero one element

	p[5][19][12][1]=0;
}

int main()
{
	// allocate 4D array, 100 x 30 x 40 x 50

	int (*arr)[30][40][50]=new int[100][30][40][50];

	// pass to function

	foo_func(arr);

	// delete array

	delete [] arr;
}

void PrintMulti(int (*a)[5]) {
	for (int i = 0; i < 5; ++i)	{
		for (int j = 0; j < 5; j++)
			cout << a[i][j] << endl;
	}
}

int main() {
	int a[5][5];
	PrintMulti(a);
	
	system("PAUSE");
	return 0;
}