Logorithms?

Possibly because it is spelled 'logarithms'.

Greetz,

Illco

Either way, it can't find it. (and google has a spell checker)

From,
Nice coder

I cannot imagine that...
Anyway a simple method for calculating the natural logarithm is this (any other can be calculated by using the rule log_ab * log_ba = 1, resulting in log_cb = log_ab / log_ac):

ln x = 2 * ( (x - 1) / (x + 1) + (x - 1)<sup>3</sup> / 3*(x - 1)<sup>3</sup> + (x - 1)<sup>5</sup> 7 5*(x + 1)<sup>5</sup> ... ) =Σ (x - 1) <sup>2i+1</sup> / (2i+1)*(x + 1)<sup>2i+1</sup> for i <= 0 <= n

This method converges slowly for x near 0 and for large values of x.
There are many other methods that converge faster - try a Wiki-page.

maybe the main thing you have to know about logarithms is
that

ln(a)+ln(b) = ln(a*b)

also

exp(a)*exp(b)=exp(a+b)

and ln(exp(x)) = x

you can also note that the derivative of
x -> ln(x)
is
x -> 1/x

you could Euler's method, though you would be better off using taylor series for logs.

Note that most log functions on calculators are base 10.

Logarithms are computed by parsing http://www.google.com/search?q=log%28138%29

Ha, ha ha. (but what happened before the big G?)

Exelant. Eulars method.

Time for [google].

From,
Nice coder