Constructors called automatically?

Original Post

Sep 16, 2006 at 9:31 AM

Hi. I ran into an interesting situation today: class A {...}; class B { B(const A &a) {...} //constructor void Foo(const B &b) {...} void FooFoo(const A &a) { Foo(a); } //!!!interesting!!! }; The above compiles fine with Visual Studio 2005. Does it mean the compiler is smart enough to invoke the constructor of B automatically in FooFoo? Or did the compiler overlook the error and I'll die at run-time?

Zao

Sep 16, 2006 at 9:45 AM

Single argument constructors may participate in implicit type conversion, which might surprise some.
If you want to protect against something like this happening, declare the offending constructor explicit.

incin

Sep 16, 2006 at 9:47 AM

Yes, the compiler is smart enough.
Use 'explicit' if you don't want that happening.

snooty

Sep 16, 2006 at 10:45 AM

Thank you for the answers.

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