convert int into const char *

Using type-casting.

But before posting very evil code to do that - why are you trying to do that?

You can either use boost::lexical_cast or a std::stringstream.

std::stringstream sstr;sstr << my_int;std::string str1 = sstr.str();std::string str2 = boost::lexical_cast<std::string>(my_int);

Once in a string, you can use the c_str() member function to get a const char *.

i want to display a message box showing x-coordiante whenever left mouse click is being done
MessageBox(NULL, some const char (i suppose),"ERROR",MB_OK|MB_ICONEXCLAMATION);

so i want to convert point.x into some character array to pass it in MessageBox
arguments

also typecasting does not work
(const char*)point.x displays empty space instead of a coordinate

how to display the coordinates in a messagebox

Quote:

Original post by mnbvlk also typecasting does not work (const char*)point.x displays empty space instead of a coordinate how to display the coordinates in a messagebox

Read SiCrane's post.

A little odd, but why has no-one yet mentioned itoa()?

personally I use _itot(...).

_itoa, _i64toa, _ui64toa, _itow, _i64tow, _ui64tow (CRT)

Its pretty simple.

First make a char.

----------------------
char StringX[5];
----------------------
next call sprintf();
----------------------

sprintf(StringX,"%d",IntX);

-------------------------
This gets String X and fills it up with IntX. Dont mind the "%d" its just a parameter.
-------------------------

int other words, this is what you need.

int iMouseX = GetMouseX() //I guess you already got that far...

char szMouseX[5];

sprintf(szMouseX,"%d",MouseX);

MessageBox(NULL,szMouseX,"ERROR",MB_OK);

Hope this helps more then it hurts

Quote:

Original post by superdeveloper A little odd, but why has no-one yet mentioned itoa()?

itoa() is a non-standard function. In fact, it's almost militantly non-standard. I've seen at least five different function signatures for itoa() over the years:

char * itoa(int, char *, int); // you supply the bufferchar * itoa(int, int, char *); // you supply the bufferchar * itoa(int, char *);      // you supply the bufferchar * itoa(int, int);         // you need to free the pointerchar * itoa(int);              // you need to free the pointer

Don't use itoa() if you even remotely care about portable code.

Quote:

Original post by Jazonxyz char szMouseX[5];

Congratulations, your code has a buffer overrun vulnerability.

Quote:

Original post by Jazonxyz sprintf(StringX,"%d",IntX);

The OP specified C++. Idiomatic C++ uses std::string for text.

Quote:

Original post by superdeveloper A little odd, but why has no-one yet mentioned itoa()? personally I use _itot(...).

Quote:

Original post by Jazonxyz Its pretty simple. First make a char. ---------------------- char StringX[5]; ---------------------- next call sprintf(); ---------------------- sprintf(StringX,"%d",IntX); ------------------------- This gets String X and fills it up with IntX. Dont mind the "%d" its just a parameter. ------------------------- int other words, this is what you need. int iMouseX = GetMouseX() //I guess you already got that far... char szMouseX[5]; sprintf(szMouseX,"%d",MouseX); MessageBox(NULL,szMouseX,"ERROR",MB_OK); Hope this helps more then it hurts

@The OP: Since you're programming in C++, I would suggest following SiCrane's suggestion instead.

Suggested reading.

Quote:

Original post by SiCrane You can either use boost::lexical_cast or a std::stringstream. std::stringstream sstr;sstr << my_int;std::string str1 = sstr.str();std::string str2 = boost::lexical_cast<std::string>(my_int); Once in a string, you can use the c_str() member function to get a const char *.

i use stringstream quite frequently in most Apps, its quite nice, and really easy to use, id also recommend this