Original Post
I realize this may be slightly off topic but I was pondering a question regarding probabilities and Texas Holdem. For those who aren't aware of how Texas Holdem works it is played from a deck of 52 cards, each player holds 2 cards each and the table can hold up to 5 which means that for 2 players there will be 9 cards in play at the end. Now for my question regarding probabilities, let's say we have the following scenario:
- We know the number of cards in our hand and on the table.
- We know the odds of beating a single opponent if the game goes to the end (i.e 7 cards become known to us).
- 2 opponents: 0.24
- 3 opponents: 0.19
- 4 opponents: 0.17
- 5 opponents: 0.15
- 6 opponents: 0.14
- 7 opponents: 0.13
- 8 opponents: 0.12
- 9 opponents: 0.21
- 2 opponents: 0.72
- 3 opponents: 0.61
- 4 opponents: 0.52
- 5 opponents: 0.44
- 6 opponents: 0.38
- 7 opponents: 0.32
- 8 opponents: 0.27
- 9 opponents: 0.23
- 2 opponents: 0.42
- 3 opponents: 0.33
- 4 opponents: 0.28
- 5 opponents: 0.24
- 6 opponents: 0.2
- 7 opponents: 0.18
- 8 opponents: 0.16
- 9 opponents: 0.14
- 2 opponents: 0.7
- 3 opponents: 0.59
- 4 opponents: 0.5
- 5 opponents: 0.43
- 6 opponents: 0.36
- 7 opponents: 0.31
- 8 opponents: 0.27
- 9 opponents: 0.23