[C++] ambiguous call to overloaded function

I have these two string conversion functions:

template <typename T> const T * UTIL::Convert(const T *, const size_t, size_t &);template <typename T, typename U> const T * UTIL::Convert(const U *, const size_t, size_t &);

The first simply returns its parameter, since they are the same type and no conversion is necessary. The second performs a conversion using wcstombs, mbstowcs, or some other method.

This line of code

const UTIL::Char * ptrText = UTIL::Convert<UTIL::Char>(p_ptrText, p_intLength, uintLength);

Produces this error

1>c:\development\assware\common\src\gui\factory.cpp(220) : error C2668: 'UTIL::Convert' : ambiguous call to overloaded function1>        c:\development\util\include\util\impl\traits.h(47): could be 'const T *UTIL::Convert<UTIL::Char,XML_Char>(const U *,const size_t,size_t &)'1>        with1>        [1>            T=UTIL::Char,1>            U=XML_Char1>        ]1>        c:\development\util\include\util\impl\traits.h(14): or       'const T *UTIL::Convert<UTIL::Char>(const T *,const size_t,size_t &)'1>        with1>        [1>            T=UTIL::Char1>        ]1>        while trying to match the argument list '(const XML_Char *, int, size_t)'

I'm wondering how to achieve the effect of automatically calling the correct Covert method using templates. That is to say, the compiler should know when the types are the same and call the first method.