binary string to decimal

[font="Consolas"][font="Consolas"]
thanks for your help in advance.[/font][/font]

Help with what? You just said "I am attempting to convert a string binary to a decimal value" but never said anything was wrong or what you needed help with or what your question is.

well I think there is a problem with this line of code.
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[font="Consolas"][/font]dec += bin[j]*2^j;[/font]

The ^ operator is not a power operator, like maths. It is the bitwise exclusive OR operator.

The value of a numberic character is not the same as the number it represents. That is, '0' != 0, '1' != 1 and so forth. In fact, the character with a value of 0 is quite special, it is used as the terminator for C strings and string literals.

A common technique to convert characters to numerics is to take advantage that in most common character encodings the numbers are contiguous and ascending. Thus, one can write:

int toNumber(char c)
{
if(c < '0' || c > '9')
{
// Errors are represented as negative result
return -1;
}
return c - '0';
}


I am attempting to convert a string binary to a decimal value.
[font="Consolas"][font="Consolas"][color="#0000ff"]...[/font][/font]
[font="Consolas"][font="Consolas"]thanks for your help in advance.[/font][/font]

Help with what? I don't see a question. I'm pretty sure I know what you're asking, but still, no question.

Did you try searching for this? It's not exactly a hard to find answer. Google returns 10,500,000 results for binary string to decimal

http://www.cplusplus.../general/13492/


Sixth post down.

EDIT:
Ninja'd by several people!

You have to take into account that your math is correct, and that of course that ^ symbol as stated is not the one you want but also:

00000010
^ = 2^8*0 ( bin[0] not bin[8] though as you have it). because you have 2^j*0 where j = 0, the first character in the string.