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wchar_t question.

Started by noxy Feb 6, 2012 at 3:50 PM 4 replies 1.9k views

Original Post

Feb 6, 2012 at 3:50 PM

In my book called symfonia c++ author wrote:

wchar_t a;
 a = L'b;

Does it mean that i must put (L) always before ('b') etc.?
I dont understand quite diffrent bettween L'b' and 'b'.

SiCrane

Feb 6, 2012 at 4:40 PM

'b' is a regular char literal. Prefixing it with L makes it a wide character literal. The same deal with quotes. "b" is a regular char string. L"b" is the wide character string with equivalent contents.

Berkay

Feb 6, 2012 at 5:06 PM

when you write L you convert 16 bit your char

SiCrane

Feb 6, 2012 at 5:10 PM

when you write L you convert 16 bit your char

No, it's not necessarily 16-bits. Most *nix systems use 32-bit wide characters.

noxy

Feb 6, 2012 at 5:29 PM

So, i must use L always when i put value in variable with wchar_t type?

SiCrane

Feb 6, 2012 at 7:10 PM

No, L is only used to prepend character literals and string literals to turn them into wide character literals and wide string literals. If you have a wchar_t variable you can assign it to another wchar_t variable without needing to use L on that assignment.

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