Original Post
[font=arial,helvetica,sans-serif]Hello Guys,[/font]
[font=arial,helvetica,sans-serif]I'm quite new in XNA 3D, and new in 3D as well, so I need a bit help about the following issue.[/font]
[font=arial,helvetica,sans-serif]I have two different models on the screen. For the left mouse click I can set the position of the model A, with the right mouse click I can do the same for model B.[/font]
[font=arial,helvetica,sans-serif]To create 3D position from mouse click I use the following method:[/font]
[font=courier new,courier,monospace]
It's working very well. The problem begins when I would like to modify the model B position programatically.
The goal what I would like to reach is if I define a new position on the screen for model B, the distance between the model A and model B position will be constant, but model B should keep the same angle\direction to the model A
Like this: http://imageupload.org/en/file/241642/problem.jpg.html
I tried to do it by myself with this method:
position of model B = GetPickedPosition(mousepos for model B) - model A position
after normalize the position of model B and finally * desired distance.
This was only an option in my many tries, but nothing worked. position of model B wasn't was when if I simply use the GetPickedPosition method.
Can anyone help me with it?
Thank you
[font=arial,helvetica,sans-serif]I'm quite new in XNA 3D, and new in 3D as well, so I need a bit help about the following issue.[/font]
[font=arial,helvetica,sans-serif]I have two different models on the screen. For the left mouse click I can set the position of the model A, with the right mouse click I can do the same for model B.[/font]
[font=arial,helvetica,sans-serif]To create 3D position from mouse click I use the following method:[/font]
[font=courier new,courier,monospace]
public static Vector3 GetPickedPosition(Vector2 position)
{
var nearSource = new Vector3(position, 0f);
var farSource = new Vector3(position, 1.0f);[/font]
[font=courier new,courier,monospace] Vector3 nearPoint = Interface.Graphics.GraphicsDevice.Viewport.Unproject(nearSource,
Camera.Projection,
Camera.View, Matrix.Identity);[/font]
[font=courier new,courier,monospace] Vector3 farPoint = Interface.Graphics.GraphicsDevice.Viewport.Unproject(farSource,
Camera.Projection,
Camera.View, Matrix.Identity);[/font]
[font=courier new,courier,monospace] Vector3 direction = farPoint - nearPoint;
direction.Normalize();[/font]
[font=courier new,courier,monospace] var r = new Ray(nearPoint, direction);[/font]
[font=courier new,courier,monospace] var n = new Vector3(0f, 1f, 0f);
var p = new Plane(n, 0f);[/font]
[font=courier new,courier,monospace] float denominator = Vector3.Dot(p.Normal, r.Direction);
float numerator = Vector3.Dot(p.Normal, r.Position) + p.D;
float t = -(numerator/denominator);[/font]
[font=courier new,courier,monospace] Vector3 pickedPosition = nearPoint + direction*t;[/font]
[font=courier new,courier,monospace] return pickedPosition;
}
It's working very well. The problem begins when I would like to modify the model B position programatically.
The goal what I would like to reach is if I define a new position on the screen for model B, the distance between the model A and model B position will be constant, but model B should keep the same angle\direction to the model A
Like this: http://imageupload.org/en/file/241642/problem.jpg.html
I tried to do it by myself with this method:
position of model B = GetPickedPosition(mousepos for model B) - model A position
after normalize the position of model B and finally * desired distance.
This was only an option in my many tries, but nothing worked. position of model B wasn't was when if I simply use the GetPickedPosition method.
Can anyone help me with it?
Thank you
