c++ pointer to member array of int

x xObj;
int *p = xObj.arr;

No,i mean with the special syntax for pointer to member,like:

x d

x* z = &d

int x::*mypointer = &x::arr;

the above would work if arr would be a simple int,not an array

I believe it would be like this.

int (x::*mypointer)[10] = &x::arr;

This is the hardest part of C++ to me and why I have had so much trouble with it. There are 3 answers to this question and all three show a different way, pointers can just be too confusing.

Yes, pointers can be confusing. But there was only one answer to this question, not three. My first response, for example, was not the kind of pointer he was looking for and thus is not an answer. Member pointers are different from pointers. My second response is the only answer in this case if he wants a member pointer to an array of 10 integers.

Also, if the wrap around syntax of array types is confusing, you can use a typedef to define the pointer type in parts:

typedef int IntArray10[10];
IntArray10 x::*mypointer = &x::arr;

@LordRhys,don't worry,I've seen a lot of code but I never actually enocuntered those pointers.I asked because I had an exercise about them.You can always make a simple pointer and point it at the array.

Even though you won't see many things used in c++,it's good to have an ideea about them,because you might encounter them once.

I've used pointer to member functions but not pointer to member variables. It's pretty rare.

Basically it's just an offset and may be useful if you want to point to one of several arrays in an object... Still pretty much a borderline case though...

I'm not even sure if the syntax is any better than the (unsafe) C way of just calculating the offset. I supose it's safer but if I was doing anything like that it would be low level and wrapped in a class anyway...