Help!

You can''t compare char arrays by just writing if (string1 == "bla bla bla"). String functions are required. strcmp() is what you''re looking for.

Invader X
Invader''s Realm

I can explain the C way to do what you''re trying to do (which is essentially the way you''ve been going so far), or I can make your life easier using (drum roll)... "The C++ Way!"

#include <iostream>
#include <string>
using namespace std;
int main(int argc, char *argv[])
{
  string name;
  cout << "What is your name?";
  getline(cin, name);
  cout << endl << endl << "Hello, " << name << endl;
  return 0;
} 

If you want to compare the input (to quit for example)

...
if(name == "quit")  // note double quotes
{
  return 0;
} 

Have fun. You can look up string, cout/cin/getline, keyword using, namespaces and the Standard Template Library (STL) in your language/compiler documentation/reference.

---

Start Here!

I tried What you sudjested Oluseyi and it works but, When I run the program it prints:

///////////////////////////
What is Your name: John doe
_

\\\\\\\\\\\\

then it waits for a second input, it dosn''t print the second one it just prints:

////////////////
hello, John doe
////////////

??????????????????????

what second input? I think you want your code to keep asking for your name then print it out repeatedly. If the name is "quit" then you want it to stop. Try with a while loop:

#include <iostream> #include <string> using namespace std; int main(int argc, char *argv[]){ string name; while(1) { cout << "What is your name? " << flush; cin >> name; if (name == "quit") break; cout << endl << "Hello, " << name << endl; } return 0; }

Of course, thats if i understood your post correctly...

Edited by - Spiral on November 29, 2001 9:45:13 AM

What he means by "second input" is that you have to hit twice before the program continues.

I have currently having the same issue b/c I am looking at STL for the first time.

#include <iostream> #include <string> using namespace std; int main() { string str; cout << "Input your name: "; getline(cin, str); cout << endl << "Your name is " << str; cout << endl; return 0; }

^^^^^^^^^^^^^^^^^^^^^^^^^
Wait, wait, wait....who's Nambla Fett?

Edited by - bassofeesh on December 7, 2001 11:38:33 PM

It''s a bug in the MSVC implementation of getline(). You can find instructions on how to fix it and other STL bugs here.

[ GDNet Start Here | GDNet FAQ | MS RTFM | STL | Google ]
Thanks to Kylotan for the idea!